Introduction
In the standard solution for the flow of a glacier down a valley, the stress state is one of pressure plus a pure shear relative to Cartesian axes aligned with the mean slope. Other stress components such as longitudinal deviatoric stress are considered to be negligible compared to those retained. A discussion of the standard solution can be found in Reference Raymond and ColbeckRaymond (1980) and the unique book by Reference HutterHutter ([CI983]). However, in some circumstances the longitudinal deviatoric stress magnitude is comparable to or exceeds the magnitude of the pure shear stress estimated in the standard solution. This would occur when the speed of the ice sliding over the bedrock is high. In particular, it seems likely that during a surge, the longitudinal deviatoric stress becomes large as the glacier stretches. This point is discussed and the results of this paper are used in a separate publication on the mechanics of surging glaciers (in preparation by the present authors). In addition, it has been found that it is necessary to take into account the longitudinal stress when using experimental measurements to relate surface and bed topography (Reference RobinRobin, 1967). Reference CollinsCollins (1968), Reference BuddBudd (1970), and Reference NyeNye (1969) have all considered this problem, and use the governing equations for equilibrium of stress, the constitutive law, and averages through the thickness of the glacier to estimate the effect of longitudinal stress on the basal shear stress. Their result for the basal shear stres
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn1.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn2.gif?pub-status=live)
where G is a function of the surface velocity, ice thickness ĥ, and material properties, and T is a function of the shear-stress distribution (α is the bed slope and ρg is the weight of the ice per unit volume). As noted by Reference NyeNye (1969), some of the derivation leading to this result is exact, while other parts are questionable. Whereas the previous work has made relatively ad hoc attempts at determining G and T, the present study determines them systematically and clarifies when the assumptions of the previous work are appropriate.
Reference HutterHutter (1981) has obtained second-order corrections to the standard glacier solution by using a regular perturbation scheme and has obtained corrections for the longitudinal stress and shear stress. This derivation is valid when the ice flux due to basal sliding is comparable to or negligible compared with the ice flux due to shear flow. Therefore, it includes, as a special case, the case of no slip at the base which was considered by Reference NyeNye (1969). Hutter’s analysis avoids considering a separate boundary layer at the free surface (Reference Johnson and McMeekingJohnson and McMeeking, 1984) by using a generalization to Glen’s flow law which predicts linearly viscous behavior at low stress levels. There may be cases, however, when such an approach cannot be used to relate surface measurements to bottom topography. The reason for this is that a boundary-layer analysis may be necessary even when linear rheology is used to model the response to low stresses. Depending on the stress level at which the transition from power-law to linear rheology takes place, it is possible for the linearly viscous region near the free surface to be very small and embedded within the boundary layer. With regard to the present paper, however, a more serious limitation of Hutter’s analysis is that when the ice flux due to basal sliding dominates the ice flux due to shear flow, the longitudinal stress magnitude is larger than that considered by Hutter. Reference FowlerFowler (1982) has considered this case, but restricted his attention to situations in which the shear stress still dominates the other deviatoric stresses.
In this paper, we are particularly interested in the following two cases: a glacier in which the longitudinal deviatoric stress is comparable to the shear stress at the base of the glacier, and a glacier in which the longitudinal stress is larger than the other stress components. We find that the state of stress in a glacier is dependent on the rate of sliding of the ice over the bedrock. It is conventional to assume that the speed of sliding is a function of the basal shear stress. This function may be monotonic for sliding without cavity formation or of the form shown in Figure 1 when cavities are present (Reference LliboutryLliboutry, 1968; Reference HutterHutter, 1982[b]). We find that the solution for portions of glaciers sliding at rates greater than
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn3.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn4.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn5.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-28144-mediumThumb-S0022143000006626_fig6g.jpg?pub-status=live)
Fig.1. Sliding law – relationship between basal shear stress and basal velocity.
In the next section, we present the governing equations for a glacier on a steep slope. In the following section, we consider the standard glacier solution which is valid for moderate basal sliding velocities. This is followed by two sections which discuss the analysis of glacier motion when the basal sliding velocity is large, i.e. when there is rapid stretching. This includes two cases in which the shear stress supports the glacier’s weight and one case in which the longitudinal deviatoric stress gradient supports part of the weight. Each case corresponds to a different magnitude of the basal sliding velocity and a different magnitude of the longitudinal deviatoric stress. We then obtain similar results for an ice mass resting on a gentle slope. Lastly, we consider the influence of the longitudinal stress on the basal shear stress for the cases studied in the previous sections.
Formulation
There have been numerous studies of the mechanics of glacial motion and a comprehensive review has been given by Reference HutterHutter (1982[a], Reference Hutter[c1983]). Following Reference Johnson and McMeekingJohnson and McMeeking (1984), we consider the gravity-driven flow of an incompressible viscous isotropic medium obeying Glen’s law down a sloping valley with slowly varying bottom topography. The flow is two-dimensional (i.e. plane strain) and inertial effects are neglected. The slope of the free surface relative to the bottom is assumed to be small and the thickness of the glacier is small compared to its down-slope extent.
We introduce a Cartesian coordinate frame (x, y) where the x-axis is along the mean bed line as in Figure 2. It should be noted that the coordinate system could also be aligned with the mean surface slope away from the margins, and the analysis would be unaltered. We first consider the case where the bed inclination angle α is assumed to be of order unity, i.e. steep glaciers, and introduce the non-dimensional variables x =
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn7.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn8.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn9.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-32439-mediumThumb-S0022143000006626_fig10g.jpg?pub-status=live)
Fig.2. A segment of the glacier showing the coordinate system.
Restricting attention to slow variations of the flow field due to steady (time averaged) accumulation and ablation, we require δ ≡ h 0/L <<1. In terms of the non-dimensional variables the governing equations become
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn12.gif?pub-status=live)
Since the glacier is shallow or thin, we see from mass conservation, i.e. Equation (2), that the transverse velocity v is small and of order δ, The constitutive equation or flow law for the ice is taken to be Glen’s law,
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-61961-mediumThumb-S0022143000006626_eqn13.jpg?pub-status=live)
where
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-37891-mediumThumb-S0022143000006626_eqn14.jpg?pub-status=live)
The boundary conditions on the upper surface of the ice y = y s (x) are those of zero traction. When trigonometric functions are expanded in terms of ys’(x) = dy s/dx, the conditions become (with reference to Figure 2)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-86866-mediumThumb-S0022143000006626_eqn15.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-28862-mediumThumb-S0022143000006626_eqn16.jpg?pub-status=live)
In addition, we have the kinematic boundary condition
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-17810-mediumThumb-S0022143000006626_eqn17.jpg?pub-status=live)
where Q is the normalized volume accumulation rate
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn18.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn19.gif?pub-status=live)
At the base of the glacier y = y b(x) we have zero normal velocity
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-56691-mediumThumb-S0022143000006626_eqn20.jpg?pub-status=live)
and a basal sliding law which we state in a general way as
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-05976-mediumThumb-S0022143000006626_eqn21.jpg?pub-status=live)
where Φ is a prescribed function of s, x, and t, and its dependence on x and t indicates that the bed can be inhomogeneous and conditions can vary with time, perhaps seasonally. The time dependence above is not intended to represent an explicit time dependence, but represents time dependence which would enter through the numerous physical mechanisms affecting Φ, such as temperature, etc. We have assumed here that the sliding mechanism is basically dominated by viscous flow and hence Φ depends principally on the deviatoric stress. However, one generalization of this would be to include pressure dependence. For example, a sliding mechanism influenced by Coulomb friction would be likely to lead to this situation.
Standard Glacier Solution
The usual solution to Equations (1) to (8) will now be summarized. The details of the perturbation methods used and the results can be found in Reference HutterHutter (1981) and Reference Morland and JohnsonMorland and Johnson (1980, Reference Morland and Johnson1982). Away from the upper surface
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-70295-mediumThumb-S0022143000006626_eqn22.jpg?pub-status=live)
where u(0) is given in Equation (10) to follow. The function C 1(x) is determined by matching with the boundary-layer solution valid near the free surface and is given by Reference Johnson and McMeekingJohnson and McMeeking (1984) as
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-48203-mediumThumb-S0022143000006626_eqn23.jpg?pub-status=live)
where the (s, n) coordinate system is shown in Figure 2,
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-15169-mediumThumb-S0022143000006626_eqn24.jpg?pub-status=live)
and r is the gamma function. (Note that C1 appearing in Reference Johnson and McMeekingJohnson and McMeeking (1984) contains an error which we have corrected here.) The stretch rates in Equation (9a) are those tangential to the top surface at the surface. C1(x) represents a shear stress induced in the core of the glacier by the relatively large longitudinal stress s xx present in the near-surface region of the glacier.
The motion of the ice is such that
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-14656-mediumThumb-S0022143000006626_eqn25.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-69923-mediumThumb-S0022143000006626_eqn26.jpg?pub-status=live)
In these equations we have recognized that the only non-zero deviatoric stress component at the base is σ xy at leading order and so to the same order the stress dependence of Φ will involve only h. That is so because h determines the basal shear stress to leading order (see Equation (9)). Lastly, the solution is completed by the determination of the glacier’s shape from the kinematic boundary condition (6).
The solution given by Equations (9) to (11) is a consistent approximation only if the basal sliding law is such that Φ = O(1) or smaller. Furthermore, the variation of ϕ with x must be O(l) or less as well. If these two conditions are met, then the stretch rate is consistent with s xx = O(δ). In addition, an examination of the kinematic boundary condition reveals that it is desirable to choose Q = O(δ) for only then is it possible that steady states (∂h/∂t = 0) could exist consistent with this solution when Q ≠ 0. In fact, the magnitude of δ can be set by defining δq(x, t) – Q(x, t) where q = O(1) and it would be sensible to choose q to have a maximum value of 1 when averaged over several years. Thus
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-80563-mediumThumb-S0022143000006626_eqn27.jpg?pub-status=live)
where
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn28.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn29.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-61622-mediumThumb-S0022143000006626_eqn30.jpg?pub-status=live)
where
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn31.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn32.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn33.gif?pub-status=live)
We note at this stage that the deviatoric stress s xx is much smaller than σ xy , except near the upper surface. To see how the magnitude of s xx can be increased we must seek ways of increasing the stretch rate ∂u/∂x. From Equation (10) we see that this can be done by increasing the magnitude of dΦ/dx to larger than O(1) or by inducing rapid variations of y s with x perhaps by a sudden local accumulation of ice or snow. In the latter case, s xx would become comparable to σ xy only when the fluctuations of y s were so rapid with x that the perturbation scheme would break down. In any case, it is unlikely that such rapid local accumulations would take place in practice. Consequently, we confine our attention to the case where the rapid stretching is induced by the sliding law.
Rapid Stretching: Shear Stress Supports Weight
We will consider the bed on which the ice slides to be such that the dimensionless basal velocity is of order 1/v, i.e. O(l/ v), where v << 1. For this to be so, the magnitude of the function Φ must be O(l/ v) and we will rewrite it as (1/ v)Φ where Φ = O(1). The magnitude of the basal velocity will determine the magnitude of the velocity in the ice as a whole and so we will consider an expansion of the form
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-72599-mediumThumb-S0022143000006626_eqn34.jpg?pub-status=live)
From this and the flow law Equation (3), it can be seen that
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-40867-mediumThumb-S0022143000006626_eqn35.jpg?pub-status=live)
Furthermore, the equilibrium Equation (1a) implies that σ xy = O(1). Therefore, if δ/v is less than or equal to order unity, i.e. δ/v ≤ O(1), then Equation (15) implies that s xx = O(δ/v) and that ∂u (–1) /∂y = 0. Hence u (–1) = u (–1)(x). Once this has been established, we see that for δ/v ≤ O(1),
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-08597-mediumThumb-S0022143000006626_eqn36.jpg?pub-status=live)
and the expansions for the stresses have the form
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-35897-mediumThumb-S0022143000006626_eqn37.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-42735-mediumThumb-S0022143000006626_eqn38.jpg?pub-status=live)
(a) Longitudinal deviatoric stress small compared to the shear stress
It now becomes necessary to consider the magnitude of δ/v versus 1. In order to give a complete discussion of the solution regimes, first consider δ/v << 1, i.e. δ << v << 1. This case has been considered by Reference FowlerFowler (1982) and from Equations (17) and (18) we see that the solution is still dominated by shear stress, since σ xy >> s xx . The solution is given by
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-13859-mediumThumb-S0022143000006626_eqn39.jpg?pub-status=live)
and of course σ xx = σ yy + 2s xx . Because the deviatoric stress is σ xy only to leading order, the function Φ will depend on the shear stress at the glacier bed, the position, and time only. From Equations (16), (19), and boundary condition (8) the ice velocity is given by
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-37758-mediumThumb-S0022143000006626_eqn40.jpg?pub-status=live)
where
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-11262-mediumThumb-S0022143000006626_eqn41.jpg?pub-status=live)
and
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-84730-mediumThumb-S0022143000006626_eqn42.jpg?pub-status=live)
The kinematic condition leads to
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-20663-mediumThumb-S0022143000006626_eqn43.jpg?pub-status=live)
Because δ/v and δ are of different orders of magnitude, it follows that q = O(1), such a case generally cannot be in equilibrium with the climate and will thin and thicken relatively rapidly until the leading term in ∂h/∂t disappears. Such behavior has been studied by Reference FowlerFowler (1982), who analyzed the kinematic waves that the process would involve. If q = O(l/v), a steady-state solution with ∂h/∂t = O(δ) could exist. As before, the complete solution might require a boundary layer near the margin. Note also from Equations (19) that there is a singularity in
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn44.gif?pub-status=live)
(b) Longitudinal deviatoric stress comparable to the shear stress
The previous case (δ<< v << 1) involves a situation in which the shear stresses σ xy are much larger than the longitudinal deviatoric stresses s xx . Thus it would not seem to be suitable for describing the mechanics of surging, where in our work in preparation on surging glaciers we have estimated s xx to be comparable with σ xy (x, y b). This has been concluded also by Reference FowlerFowler (1982) for the different reason that the glacier would merely generate kinematic waves in response to seasonal changes. Furthermore, the expansion would break down and the solution would be inappropriate if ∂Φ/∂x became very large anywhere and such a phenomenon is often suggested as the basis for surging models. Instead, we will consider the case in which v = 0(δ) and, without losing any generality, we can identify v with δ. This corresponds to a situation in which the magnitude of the longitudinal deviatoric stress is comparable to that of the shear stress.
In this situation, the stresses would have the form
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-94610-mediumThumb-S0022143000006626_eqn45.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-44909-mediumThumb-S0022143000006626_eqn46.jpg?pub-status=live)
As a consequence
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-88380-mediumThumb-S0022143000006626_eqn47.jpg?pub-status=live)
and the flow law gives
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-10311-mediumThumb-S0022143000006626_eqn48.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-57225-mediumThumb-S0022143000006626_eqn49.jpg?pub-status=live)
From the boundary conditions on y = y s we find
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-19984-mediumThumb-S0022143000006626_eqn50.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-18148-mediumThumb-S0022143000006626_eqn51.jpg?pub-status=live)
and on y = Y b
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-63144-mediumThumb-S0022143000006626_eqn52.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-31987-mediumThumb-S0022143000006626_eqn53.jpg?pub-status=live)
The equilibrium Equations (2) become at first and second order, respectively
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-80266-mediumThumb-S0022143000006626_eqn54.jpg?pub-status=live)
and
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-38294-mediumThumb-S0022143000006626_eqn55.jpg?pub-status=live)
We find by integrating Equations (31) using boundary conditions (27) and (28) that
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-13040-mediumThumb-S0022143000006626_eqn56.jpg?pub-status=live)
as the down-slope component of weight is still supported by the shear stress.
The boundary condition (30) and (25) together provide an equation for
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn57.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-48580-mediumThumb-S0022143000006626_eqn58.jpg?pub-status=live)
Here we will use the conventional assumption that the sliding velocity at the base depends only on the basal shear stress. In this case u (−1)(x) will be known in terms of the bed shear stress and therefore in terms of the profile of the glacier. Consequently, du (−1)/dx is then known and Equation (34) is a cubic algebraic equation for
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn59.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn60.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn61.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn62.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn63.gif?pub-status=live)
Returning to the conventional case where Equation (34) is simply a cubic algebraic equation, we find it has only one real root
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-60605-mediumThumb-S0022143000006626_eqn64.jpg?pub-status=live)
where
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-04039-mediumThumb-S0022143000006626_eqn65.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-40294-mediumThumb-S0022143000006626_eqn66.jpg?pub-status=live)
where
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-65143-mediumThumb-S0022143000006626_eqn67.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-41157-mediumThumb-S0022143000006626_eqn68.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-34980-mediumThumb-S0022143000006626_eqn69.jpg?pub-status=live)
and I 1 is plotted against z in Figure 4. When z is small compared to unity, I 1 can be neglected.
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-56052-mediumThumb-S0022143000006626_fig70g.jpg?pub-status=live)
Fig.4. Functions arising in expressions for stress in glaciers. The solid line is I1(z) and the dashed line is with that of I2(z)
Next, we can integrate Equation (26) to obtain
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-84288-mediumThumb-S0022143000006626_eqn71.jpg?pub-status=live)
although we do not yet know
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn72.gif?pub-status=live)
Finally, we can use incompressibility to find
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-72365-mediumThumb-S0022143000006626_eqn73.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-95449-mediumThumb-S0022143000006626_eqn74.jpg?pub-status=live)
It is of some interest to consider the solution when Φ(
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn75.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-58330-mediumThumb-S0022143000006626_eqn76.jpg?pub-status=live)
just as it would be in the previous case when v << δ, except now the smallness of
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn28.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-17290-mediumThumb-S0022143000006626_eqn78.jpg?pub-status=live)
This integrates to give
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-27606-mediumThumb-S0022143000006626_eqn79.jpg?pub-status=live)
It is important to note that in the solutions obtained so far the down-slope component of weight is supported by the basal shear stress to leading order. In general, the higher-order terms will alter the basal shear stress so that it is not exactly equal to the down-slope weight, but of course this correction is small. As mentioned previously, the expansion breaks down in certain circumstances. Consider sliding laws of the kinds shown in Figure 1. Assume that for some reason the basal shear stress, computed to leading order as h sin ɑ, is comparable with τm. This could occur because of high lubrication due to excess water in the melt season, which could cause the glacier to slide relatively rapidly at low basal shear stress. In regions moving slower than u1 b, h sin ɑ < τm and, as long as that condition is met, the preceding solutions can be used. However, as h sin ɑ approaches τm, say in a thicker portion of the glacier, then ∂Φ/∂τb becomes very large. In fact, at 1, ∂Φ/∂τb = ∞ and therefore according to Equation (37) u (0)→ ∞. This means that u (0) will exceed the leading-order approximation for velocity u (–1) /δ = Φ/δ and the expansion has broken down. In addition, if h sin ɑ exceeds τm as it would do in general for sliding speeds exceeding u 1 b between points 1 and 2 in Figure 1, then the down-slope component of weight can no longer be supported by basal shear stress to leading order. Since the leading-order equations can no longer be satisfied, the perturbation expansion has broken down and the approximations are no longer valid. Of course, if the sliding speed exceeds u 2 b in Figure 1, then with sliding law (a) the basal shear stress could match h sin ɑ once more. Because the velocity is a continuous function of position, there may be a substantial portion of the glacier sliding at speeds between 1 and 2 and, if we are dealing with law (b), there could be large portions of the glacier where h sin ɑ exceeds τb. Thus it is interesting to consider such a possibility and this is dealt with in the next section.
Rapid Stretching: Longitudinal Stress Gradient Supports Part of the Weight
Beyond the peak in Figure 1, some portion of the down-slope component of weight is borne by the longitudinal stress gradient to leading order. As this is not the case in the results discussed so far, we must seek another solution. We shall study now the situation where v << δ so that s xx dominates σ xy . In particular, we are considering the case in which some of the glacier’s weight is supported by σ xx and we see from the equilibrium Equations (1) that this requires
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-15360-mediumThumb-S0022143000006626_eqn80.jpg?pub-status=live)
from which it follows that
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-18116-mediumThumb-S0022143000006626_eqn81.jpg?pub-status=live)
As before σ (0) yy = (y – y b)cos ɑ. From the flow law, Equation (3), we find that
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-09815-mediumThumb-S0022143000006626_eqn82.jpg?pub-status=live)
and
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-60225-mediumThumb-S0022143000006626_eqn83.jpg?pub-status=live)
Consequently, these can be satisfied to leading order if we require
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-45610-mediumThumb-S0022143000006626_eqn84.jpg?pub-status=live)
giving
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-60402-mediumThumb-S0022143000006626_eqn85.jpg?pub-status=live)
From the equilibrium Equation (1a) it follows that
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-48441-mediumThumb-S0022143000006626_eqn86.jpg?pub-status=live)
and thus
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-14646-mediumThumb-S0022143000006626_eqn87.jpg?pub-status=live)
The boundary condition at y = y s is given by
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-91773-mediumThumb-S0022143000006626_eqn88.jpg?pub-status=live)
and together with Equation (45) this gives
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-80113-mediumThumb-S0022143000006626_eqn89.jpg?pub-status=live)
If we restate the sliding law as
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-98936-mediumThumb-S0022143000006626_eqn90.jpg?pub-status=live)
where Φ is O(1) we can consider the inversion
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-45707-mediumThumb-S0022143000006626_eqn91.jpg?pub-status=live)
in which we take Φ−1 to be a single-valued function of u (−4) as it would be in the two cases illustrated in Figure 1.
The differential Equation (46) must be solved with appropriate boundary conditions. If we consider a segment AB as in Figure 3 in which this solution is valid, then boundary conditions are required at A and B. Outside AB, we shall assume that the ice is moving slowly and the down-slope component of weight is supported by the basal shear stress to leading order. This means that the basal velocity is O(1/δ) at most outside AB. Near A and B the perturbation approximation for basal velocity of O(1/δ) will break down. However, we shall assume that the ice velocities are O(1/δ) at A and B. This means that u (–4) in AB must vanish at A and B, giving us an ad hoc matching to the more slowly moving ice on either side. This somewhat ad hoc matching condition is consistent with mass conservation and assumes that the local regions near A and B are relatively passive. Rigorously derived matching conditions would require the determination of the local solutions valid near the transition points A and B and this is not an easy task in the present problem. However, in defense of the approach taken here, it is quite common in perturbation problems of this type to find that the local solutions are passive. Therefore assuming u(4) vanishes at A we then note that
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-95204-mediumThumb-S0022143000006626_eqn92.jpg?pub-status=live)
since
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-36117-mediumThumb-S0022143000006626_eqn93.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn94.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn95.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn96.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-64812-mediumThumb-S0022143000006626_fig97g.jpg?pub-status=live)
Fig.3. Schematic of a rapidly sliding glacier segment constrained by slowly moving portions.
The integro-differential Equation (46) involves the balance between the body force h sin ɑ, the stress resultant
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn98.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn99.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn100.gif?pub-status=live)
Glaciers on a Gentle Slope
In the previous sections we have been concerned with glaciers moving down moderate slopes. We will now consider the case of gentle slopes. When the average slope for the glacier is O(δ), we can rewrite sin ɑ as βδ and cos ɑ as
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn101.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-97591-mediumThumb-S0022143000006626_eqn102.jpg?pub-status=live)
where for consistency Φ = O(δ3). As before, there is a boundary layer near the free surface as discussed by Reference Johnson and McMeekingJohnson and McMeeking (1984). Note that, since the slope is small, the force due to gravity which drives the ice down the incline is of the same order of magnitude as the driving force due to gravity which causes the ice to flow from deep to shallow regions. Furthermore, in the standard solution both of these are balanced by the shear stress and the longitudinal deviatoric stress is higher order.
If, on the other hand, we consider the case when s xx = o(δ) and therefore comparable to σ xy , we then must have
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-67133-mediumThumb-S0022143000006626_eqn103.jpg?pub-status=live)
where
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-63053-mediumThumb-S0022143000006626_eqn104.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn105.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-31873-mediumThumb-S0022143000006626_eqn106.jpg?pub-status=live)
This is very similar to Equation (34) and when δ 2 u (2)(x) = Φ(δτb (1)) depends only on the basal shear stress. The cubic equation will have a solution of the form of Equation (35). At higher order we find
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-10064-mediumThumb-S0022143000006626_eqn107.jpg?pub-status=live)
where
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-38784-mediumThumb-S0022143000006626_eqn108.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-71733-mediumThumb-S0022143000006626_eqn109.jpg?pub-status=live)
and I 1(z) is given in Equations (36), I 1 and I 2 are plotted against z in Figure 4. When z is small compared to unity, I 1 and I 2 can be neglected. In addition
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-88547-mediumThumb-S0022143000006626_eqn110.jpg?pub-status=live)
Note that this solution contains the standard solution as a special case since it can be recovered by allowing Φ to become smaller than O(δ2).
We can also consider the situation when Φ = O(δ) which corresponds to large longitudinal deviatoric stresses compared to shear stress. However, again the shear stress will be balancing the driving forces due to gravity. In this case we have
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-46331-mediumThumb-S0022143000006626_eqn111.jpg?pub-status=live)
with
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-82955-mediumThumb-S0022143000006626_eqn112.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-99386-mediumThumb-S0022143000006626_eqn113.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn114.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-59979-mediumThumb-S0022143000006626_eqn115.jpg?pub-status=live)
Note that u(2) = u (2)(x) and shearing flow appears only at O(δ7/3). A similar solution can be found for Φ = O(1) in which case u = O(1) and s xx = O(δ1/3). However, we will consider next the situation when Φ is large and the forces due to gravity are not balanced by the shear stress atone.
In this situation
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-99141-mediumThumb-S0022143000006626_eqn116.jpg?pub-status=live)
with
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-96941-mediumThumb-S0022143000006626_eqn117.jpg?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-02251-mediumThumb-S0022143000006626_eqn118.jpg?pub-status=live)
which gives at the base
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-20485-mediumThumb-S0022143000006626_eqn119.jpg?pub-status=live)
If the velocity at the bed depends on the shear stress, Equation (59) is an integro-differential equation in x and it must be solved with boundary conditions on the stress or velocity given at two values of x in a manner similar to the steep-slope case.
Corrected Shear Stress at the Base
We will now consider how the longitudinal stress gradient influences the shear stress at the base by introducing corrections to the leading-order estimate. Attempts have been made by various workers (Reference RobinRobin, 1967; Reference CollinsCollins, 1968; Reference NyeNye, 1969; Reference BuddBudd, 1970; Reference HutterHutter, 1981) to find this relationship in connection with experiments to relate bottom and surface topography. Their technique is to start with the exact equations, integrate through the glacier thickness and make assumptions about dropping terms and then invoke the constitutive law. The simplest form of their result can be stated as
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-42549-mediumThumb-S0022143000006626_eqn120.jpg?pub-status=live)
where T is the shear stress σ xy integrated twice through the thickness and
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-26512-mediumThumb-S0022143000006626_eqn121.jpg?pub-status=live)
with the sign chosen to agree with that of
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn122.gif?pub-status=live)
First, we consider the standard case for the steep glacier which would be valid when it is stuck to the bedrock. This is the case considered by Reference NyeNye (1969). From the first of Equations (9) we find
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-56822-mediumThumb-S0022143000006626_eqn123.jpg?pub-status=live)
with the sign chosen to agree with that of
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn124.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn125.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-89159-mediumThumb-S0022143000006626_eqn126.jpg?pub-status=live)
or 35/3 k/2 times the ratio of the surface longitudinal stress to the basal shear stress estimated to leading order. The parameter k is given in Equation (9a). Of course, Budd, Collins, and Nye were unaware of the boundary layer and instead tried to estimate the relationship between the average longitudinal deviatoric stress and the surface strain-rate to obtain their G.
The influence of the boundary layer on shear stress can be understood from the following simple model. Consider the region near the free surface. It is stretching or compressing to leading order and this requires a longitudinal stress deviator. Twice the longitudinal gradient of this stress integrated through the thickness of the boundary layer must be balanced by a shear stress at the bottom of the layer. To the underlying ice, this stress appears as if it is a non-zero shear stress at the upper free surface. Reference Johnson and McMeekingJohnson and McMeeking (1984) have shown that the boundary-layer thickness is δ1/3 ĥ so with ŷ s’(
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn127.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-61121-mediumThumb-S0022143000006626_eqn128.jpg?pub-status=live)
which is almost identical to the results of Collins and Nye except that the integration is carried out only in the boundary layer. The last term in Equation (61) is an evaluation of this integral.
In the case of the standard glacier solution on the gentle slope, Reference Johnson and McMeekingJohnson and McMeeking (1984) did not carry out the matching to sufficient terms for the result we wish. However, the situation is likely to be similar to the steep-slope case.
Next consider the case when there is substantial sliding at the bed. For the steep glacier which is stretching rapidly so that the longitudinal deviatoric stress is comparable to the shear stress, we find from Equations (33) and (36) that when ɑ is chosen so that y s’(x) = 0
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-70463-mediumThumb-S0022143000006626_eqn129.jpg?pub-status=live)
where
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-20920-mediumThumb-S0022143000006626_eqn130.jpg?pub-status=live)
and I 1 is plotted versus z in Figure 4. It can be seen that the result for this case bears some similarity to the standard glacier formula of Equation (61). In addition, from Equation (53) we see that the result for a glacier on a gentle slope in which the longitudinal deviatoric stress is comparable with the shear stress (with ɑ chosen to make ŷ’ s(
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn131.gif?pub-status=live)
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary-alt:20171010065708-61399-mediumThumb-S0022143000006626_eqn132.jpg?pub-status=live)
where
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn133.gif?pub-status=live)
Another solution on the gentle slope is given by Equation (55), where the leading-order velocity is O(δ) and is independent of depth, but the down-slope component of weight is supported by basal shear stress to leading order. In this case, the longitudinal deviatoric stress is O(l/δ1/3) larger than the shear stress. From Equations (55) and (56) we find that, when ɑ is chosen so that ŷ s’(
![](https://static.cambridge.org/binary/version/id/urn:cambridge.org:id:binary:20171010042320422-0066:S0022143000006626:S0022143000006626_eqn134.gif?pub-status=live)
Finally, we consider the case where the down-slope component of weight is partly borne by the longitudinal stress gradient to leading order. The fact that the leading-order longitudinal deviatoric stress is independent of depth makes it clear that Equation (60) with T omitted gives the corrected basal shear stress both for the gentle and steep cases.
Summary
In the present paper we have examined glacial flow in cases where the longitudinal deviatoric stress becomes large. In particular, we have developed the theory for the case when the longitudinal deviatoric stress is comparable to the shear stress and the case when the longitudinal stress is the dominant stress component. In each case the stress state is strongly influenced by the character of the basal sliding. Furthermore, the stress state in these cases differs fundamentally from that of the standard solution where the shear stress is dominant and supports the weight. Lastly, we examined the effect of the longitudinal stress on the basal shear stress and compared the results with previous work on relating surface and bottom topography.
Acknowledgement
This research was carried out while the authors were supported by National Science Foundation grants MEA 82–11018 (RMM) and MEA 83–11495 (REJ).