The publisher apologises that upon publication an error was made in the equation listed for (4.3c) with + having been replaced in error with an x.
The correct equation is below:
(4.3c)
\begin{align} 0 &= \int_{-{1}/{2}}^{{1}/{2}} \left[\frac{(1-\cos{\theta_0})}{q_0} +\frac{F_0^2 \theta_0^{\prime}}{2}(2 \cos{\theta_0}-q_0-q_0^2\cos{\theta_0}) \right.\nonumber\\ &\quad +(3\cos{\theta_0}-2q_0-q_0^2\cos{\theta_0})\left(\frac{F_0^3F_1(1-q_0^2)}{2q_0}-\frac{F_0^4q_1}{8q_0}(1+q_0^2)\right)\nonumber\\ &\quad \left.+\,\frac{F_0^4(1-q_0^2)}{8q_0}({-}3\theta_1\sin{\theta_0}-2q_1+q_0^2\theta_1\sin{\theta_0}-2q_0q_1\cos{\theta_0})\right]{{\rm d}}{} \phi. \end{align}
\begin{align} 0 &= \int_{-{1}/{2}}^{{1}/{2}} \left[\frac{(1-\cos{\theta_0})}{q_0} +\frac{F_0^2 \theta_0^{\prime}}{2}(2 \cos{\theta_0}-q_0-q_0^2\cos{\theta_0}) \right.\nonumber\\ &\quad +(3\cos{\theta_0}-2q_0-q_0^2\cos{\theta_0})\left(\frac{F_0^3F_1(1-q_0^2)}{2q_0}-\frac{F_0^4q_1}{8q_0}(1+q_0^2)\right)\nonumber\\ &\quad \left.+\,\frac{F_0^4(1-q_0^2)}{8q_0}({-}3\theta_1\sin{\theta_0}-2q_1+q_0^2\theta_1\sin{\theta_0}-2q_0q_1\cos{\theta_0})\right]{{\rm d}}{} \phi. \end{align}Additionally a semi-colon was listed with in the second point within the conclusions section that was not required. The correct text is as below
(ii) optimally truncating the divergent expansion at
$N \sim 1/B$ and considering the exponentially small remainder $\bar {q}$ by a solution of the form $q=q_0+Bq_1+ \cdots$ $+ B^N q_N + \bar {q}$;
