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Proof that every rational algebraic equation has a root
Published online by Cambridge University Press: 20 January 2009
Extract
The following arrangement of the proof of this theorem could, I think, be given at a comparatively early stage, even if the necessary case of De Moivre's theorem had to be proved as an introductory lemma.
Let u, v be two rational integral algebraic functions of x, y with real coefficients, and let c be a simple closed contour in the plane. As the point (x, y) travels round c let those changes in the sign of u that take place when v is positive be marked and let (u, v; c) denote the excess in number among these of changes from + to − over changes from − to + *.
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- Copyright © Edinburgh Mathematical Society 1907
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* It is not hard to see that (v, u; c) = (−u, v; c)= − (u, v; c) etc.