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On a Geometrical Problem
Published online by Cambridge University Press: 20 January 2009
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Stewart, a Scotch geometrician, gave in 1763 the demonstration of the following theorem: “If we divide the base of a triangle into two segments by a straight line going through the vertex, the sum of the squares of the two sides, multiplied each by the non-adjacent segment, is equal to the product of the base multiplied by the square of the straight line plus the rectangle contained by the two segments.”
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- Copyright © Edinburgh Mathematical Society 1897
References
* Sur le théorème de Stewart (Revue de I'Instruction Publique), Bruxelles, 1887; applications remarquables du théorème de Stewart et theorie du barycentre, Bruxelles, 1891.
† El Progreso Matemático, Zaragoza, 1892, pp. 62, 94, 124.Google Scholar
‡ Clément Thiry, Op. cit., p. 6.
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