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Representations of quadratic forms
Published online by Cambridge University Press: 22 January 2016
Extract
We have shown in [1]
Theorem A. Let L be a lattice in a regular quadratic space U over Q; then L has a submodule M satisfying the following conditions 1),2):
1) dM ≠ 0, rank M = rank L — 1, and M is a direct summand of L as a module.
2) Let L′ be a lattice in some regular quadratic space U′ over Q satisfying dL′ = dL, rank L′ — rank L, tp(L′) ≥ tp(L) for any prime p. If there is an isometry α from M into L′ such that α(M) is a direct summand of L′ as a module, then L′ is isometric to L.
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- Copyright © Editorial Board of Nagoya Mathematical Journal 1978