The lattice properties of asymmetric hyperbolic regions
II. On a theorem of davenport
Published online by Cambridge University Press: 24 October 2008
Extract
In this paper, all numbers are real and all radicals are positive.
Let f(x, y) = ax2 + bxy + cy2 be an indefinite quadratic form, and let d = Δ2 = b2 − 4ac, where Δ > 0. A well-known theorem of Minkowski states that, if (x0, y0) is any pair of numbers, then there exists a pair (x, y), x ≡ x0 (mod 1), y ≡ y0 (mod 1), say (x, y) ≡ (x0, y0) (mod 1), such that
for k ≥ ¼, and Davenport has shown how this result may be improved if we know a value assumed by f(x, y) for coprime integral values, (x, y) = (m, n) ≠ (0, 0). In this paper, we discuss the more general inequality
where R and S are constants, and use the method developed in the first paper of this series to obtain a sharper and more general theorem than Davenport's. We give an application to the theory of real Euclidean quadratic fields and to a problem in Diophantine approximation discussed by Khintchine.
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- Information
- Mathematical Proceedings of the Cambridge Philosophical Society , Volume 44 , Issue 2 , April 1948 , pp. 145 - 154
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- Copyright © Cambridge Philosophical Society 1948
References
† Davenport, , Proc. K. Akad. Wet. Amsterdam, 49 (1946), 815–21.Google Scholar This paper used elementary methods. In two subsequent papers, ibid. 50 (1947), 378–89 and 484–91, Prof. Davenport uses deeper methods to discuss completely x 2 + xy − y 2 and 5x 2 + 11xy − 5y 2.
‡ Cassels, , Proc. Cambridge Phil. Soc. 44 (1948), 1–7.CrossRefGoogle Scholar
§ Khintchine, , Bull. Acad. Sci. U.R.S.S. 10 (1946), 281–93.Google Scholar
∥ For a definition of the lattice-theoretic terms employed, see my earlier paper.
† See Fig. 1.
‡ In this and later applications of the lemma, the points A, B, C, D do not necessarily correspond to the points so named in the enunciation of the lemma. Here, for instance, A, B, Ā correspond to A, B, C, D respectively in the lemma.
† See Fig. 2.
‡ See Fig. 3.
† In the wide sense, i.e., of determinant ± 1.
‡ As I know of no reference to exactly what is required, I sketch a proof from first principles: As (X 1, Y 1) ≠ (0, 0), at least one of the two transformations
is non-degenerate, and the transform (X′1, Y′1) of (X 1, Y 1) lies in either case on the X′-axis (i.e. X′1 ≠ Y′1 = 0). We assume T non-degenerate, and write
If f(X 1, Y 1) = f′(X′1, 0) = 0, then a′ = 0, but, as Δ ≠ 0, necessarily b′ ≠ 0. Hence f(X, Y) = X″ Y″ where the transformation
is non-degenerate, and the ambiguous sign is such that X″1 > 0 (with the obvious meaning for X″1). If, however, f(X 1, Y 1) = f′(X′1, 0) > 0, then a′ > 0 and
where b′2 − 4a′c′ > 0. The transformation
is real and non-degenerate, and the ambiguous sign may be taken so that X″1 > 0. Hence
If f(X, Y 1) < 0, we put − f(X, Y) for f(X, Y) in the foregoing analysis. In any case, we now write
where, as (X″, Y″) is connected to (X, Y) by a chain of non-degenerate linear substitutions, we may choose ρ > 0 so that the substitution linking x, y to X, Y is unimodular. Finally, the numerical coefficient in the expressions Δxy and ½Δ(x2 − y2) is a consequence of the well-known invariance of the discriminant under unimodular substitution.
† That is, the covariant 2amμ + b(mν + μn) + 2cnν vanishes.
† For there exists an integer M such that Mf(X, Y) = F(X, Y) has integral coefficients and so, by Landau, Vorlesungen (Leipzig, 1927) Satz 202 (vol. 1, p. 139), has an infinity of automorphisms. We take for (m 1, n 1) the image of (m, n) under any automorphism.
‡ Loc. cit. in § 1.
§ Loc. cit.
† And also for t = 19, 57, 73 and 97; but this is more difficult. It is not known if this is all, but any more values of t must be primes congruent to 1 (mod 24). See Redei, L., Math. Ann. 118 (1942), 588–608CrossRefGoogle Scholar, which has an almost complete list of references. For an elementary account of the Euclidean Algorithm see Hardy, G. H. and Wright, E. M., Introduction to the Theory of Numbers (Oxford, 1938)Google Scholar, § 14·8.
† If (a, b) and (c, d) are two points and (A, B), (C, D) their respective transforms under unimodular transformation, then
To obtain (12) from Lemma 2 write
(a, b) = (x, y), (A, B) = (x k, y k), (c, d) = (ξ, 0) and (C, D) = (m k, n k).
† Loc. cit. § 1.
‡ Cassels, loc. cit.
§ Davenport, H. and Heilbronn, H., 'On asymmetric inequalities for the product of two non-homogeneous linear forms', J. London Math. Soc. 22 (1947), 53–61.CrossRefGoogle Scholar I am grateful to Prof. Davenport for telling me of this paper, and also for pointing out the paper by Khintchine.
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