Hostname: page-component-78c5997874-mlc7c Total loading time: 0 Render date: 2024-11-09T14:30:23.535Z Has data issue: false hasContentIssue false
  • English
  • Français

62.8 tan−1 ½ + tan−1 ⅓= 45°

Published online by Cambridge University Press:  22 September 2016

D. M. Hallowes
D. M. Hallowes*
Affiliation:
Heath School, Halifax
Get access Rights & Permissions [Opens in a new window]

Abstract

An abstract is not available for this content so a preview has been provided. Please use the Get access link above for information on how to access this content.
Image of the first page of this content. For PDF version, please use the ‘Save PDF’ preceeding this image.'
Type
Notes
Information
The Mathematical Gazette , Volume 62 , Issue 419 , March 1978 , pp. 53 - 54
Copyright
Copyright © Mathematical Association 1978

Access options

Get access to the full version of this content by using one of the access options below. (Log in options will check for institutional or personal access. Content may require purchase if you do not have access.)