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Tchebycheff's mean value theorem and some results derivable therefrom
Published online by Cambridge University Press: 11 August 2014
Extract
f(x), f′(x),…, f(n+1)(x) are one-valued, finite and continuous (v≤x≤w).
Define
Then*
u (x) is one-valued, finite and continuous (v ≤ x ≤ w).
by writting
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- Research Article
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- Copyright
- Copyright © Institute of Actuaries Students' Society 1947
References
page 70 note * By successive partial integration of the equation
page 70 note † A sufficient Gegenbeispiel for the hypothesis that v≤xp≤w, p=1, 2, …, n, is provided by: u (x) = 1/(1·01–x), n = 2, v = 0, w = 1. The solution is m 1 = ·793, m 2 = ·693 giving x 1 = 1·046, x 2 = ·541. In any such case it is necessary to extend the bounded interval for which f (x) is one-valued, finite and continuous to include all values of xp .
page 71 note * Because
page 75 note * Some of this information was kindly supplied by John Brown and Co. of Clydebank.
page 75 note † . See Biometrika, Vol. IV (1905/1906), Part III, p. 379 Google Scholar; J.I.A. Vol. XL (1906), p. 117 Google Scholar; Attwood's, Theoretical Naval Architecture, p. 12 Google Scholar; A.M. p. 307; M.A.S., Part II, p. 196.
page 76 note *
page 76 note †
page 80 note * Accurate values were found from the formulae