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ANALYTIC EQUIVALENCE RELATIONS SATISFYING HYPERARITHMETIC-IS-RECURSIVE

Part of: Set theory Computability and recursion theory

Published online by Cambridge University Press:  27 April 2015

ANTONIO MONTALBÁN
ANTONIO MONTALBÁN*
Affiliation:
Department of Mathematics, University of California, Berkeley, USA; [email protected]

Abstract

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We prove, in $\text{ZF}+\boldsymbol{{\it\Sigma}}_{2}^{1}$-determinacy, that, for any analytic equivalence relation $E$, the following three statements are equivalent: (1) $E$ does not have perfectly many classes, (2) $E$ satisfies hyperarithmetic-is-recursive on a cone, and (3) relative to some oracle, for every equivalence class $[Y]_{E}$ we have that a real $X$ computes a member of the equivalence class if and only if ${\it\omega}_{1}^{X}\geqslant {\it\omega}_{1}^{[Y]}$. We also show that the implication from (1) to (2) is equivalent to the existence of sharps over $ZF$.

MSC classification

Primary: 03E15: Descriptive set theory
Secondary: 03D60: Computability and recursion theory on ordinals, admissible sets, etc.
Type
Research Article
Information
Forum of Mathematics, Sigma , Volume 3 , 2015 , e8
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Creative Commons
Creative Common License - CCCreative Common License - BY
This is an Open Access article, distributed under the terms of the Creative Commons Attribution licence (http://creativecommons.org/licenses/by/3.0/), which permits unrestricted re-use, distribution, and reproduction in any medium, provided the original work is properly cited.
Copyright
© The Author 2015

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