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If ABDC be a parallelogram, of which AD is a diagonal, and if 0 be any point which, by joining
to A, B, C, D, makes three triangles, OAB, OAD, OAC, each of these being taken as positive in sign so long as O lies within the region selected (i.e. within ABD), then:
ΔOAC – ΔOAB = ΔOAD.
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- Copyright © Edinburgh Mathematical Society 1915