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A geometrical proof of

Published online by Cambridge University Press:  31 October 2008

A. D. Russell
A. D. Russell
Affiliation:
12 Heugh Street, Falkirk.
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In the figure, ABC is a triangle with B > C; AF is made equal to AC, AE bisects the angle A, and BDEG is a rectangle. It is easily seen that the angles marked α are equal, that B − α = C + α, and hence that α = ½ (B − C). Then:

Type
Research Article
Information
Edinburgh Mathematical Notes , Volume 35 , January 1945 , pp. 9
Copyright
Copyright © Edinburgh Mathematical Society 1945