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Injective Convolution Operators on ℓ∞(Γ) are Surjective
Published online by Cambridge University Press: 20 November 2018
Abstract
Let $\Gamma $ be a discrete group and let $f\,\in \,{{l}^{1}}(\Gamma )$. We observe that if the natural convolution operator $\rho f\,:\,{{l}^{\infty }}(\Gamma )\,\to \,{{l}^{\infty }}(\Gamma )$ is injective, then $f$ is invertible in ${{l}^{1}}(\Gamma )$. Our proof simplifies and generalizes calculations in a preprint of Deninger and Schmidt by appealing to the direct finiteness of the algebra ${{l}^{1}}(\Gamma )$.
We give simple examples to show that in general one cannot replace ${{l}^{\infty }}$ with ${{l}^{p}},\,1\,\le \,p\,<\,\infty $, nor with ${{L}^{\infty }}(G)$ for nondiscrete $G$. Finally, we consider the problem of extending the main result to the case of weighted convolution operators on $\Gamma $, and give some partial results.
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- Copyright © Canadian Mathematical Society 2010