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Artinian Local Cohomology Modules

Published online by Cambridge University Press:  20 November 2018

Keivan Borna Lorestani ,
Parviz Sahandi  and
Siamak Yassemi
Keivan Borna Lorestani
Affiliation:
Department of Mathematics, University of Tehran, Tehran, Iran e-mail: [email protected]
Parviz Sahandi
Affiliation:
Center of Excellence in Biomathematics, School of Mathematics, Statistics and Computer Science, University of Tehran, Tehran, Iran andSchool of Mathematics, Institute for Studies in Theoretical Physics and Mathematics, Tehran, Iran e-mail: [email protected]@ipm.ir
Siamak Yassemi
Affiliation:
Center of Excellence in Biomathematics, School of Mathematics, Statistics and Computer Science, University of Tehran, Tehran, Iran andSchool of Mathematics, Institute for Studies in Theoretical Physics and Mathematics, Tehran, Iran e-mail: [email protected]@ipm.ir
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Abstract

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Let $R$ be a commutative Noetherian ring, $\mathfrak{a}$ an ideal of $R$ and $M$ a finitely generated $R$-module. Let $t$ be a non-negative integer. It is known that if the local cohomology module $\text{H}_{\mathfrak{a}}^{i}\,\left( M \right)$ is finitely generated for all $i\,<\,t$, then $\text{Ho}{{\text{m}}_{R}}\,\left( R/\mathfrak{a},\,\text{H}_{\mathfrak{a}}^{t}\,\left( M \right) \right)$ is finitely generated. In this paper it is shown that if $\text{H}_{\mathfrak{a}}^{i}\,\left( M \right)$ is Artinian for all $i\,<\,t$, then $\text{Ho}{{\text{m}}_{R}}\,\left( R/\mathfrak{a},\,\text{H}_{\mathfrak{a}}^{t}\,\left( M \right) \right)$ need not be Artinian, but it has a finitely generated submodule $N$ such that $\text{Ho}{{\text{m}}_{R}}\left( R/\mathfrak{a},\text{H}_{\mathfrak{a}}^{t}\left( M \right) \right)/N$ is Artinian.

Keywords

13D4513E1013C05local cohomology moduleArtinian modulereflexive module
Type
Research Article
Information
Canadian Mathematical Bulletin , Volume 50 , Issue 4 , 01 December 2007 , pp. 598 - 602
Copyright
Copyright © Canadian Mathematical Society 2007

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