CHAPTER IV - Piecewise hereditary algebras
Published online by Cambridge University Press: 28 January 2010
Summary
Piecewise hereditary algebras
We call a finite-dimensional k-algebra A piecevise hereditary if Db(A) is triangle-equivalent to Db(kΔ) for some finite quiver Δ without oriented cycle. We recall that Δ is uniquely determined up to the relation ∼ introduced in I. 5.7. In this section we present some general facts about piecewise hereditary algebras. But first we need to recall some elementary facts for hereditary finite-dimensional k-algebras.
LEMMA. Let B be a hereditary finite-dimensional k-algebra and let X1,X2,X3 be B-modules. Suppose that f: X1 → X2 is subjective and that g: X2→ X3 is injective. Then there exists a module Y and linear maps h1: X1 → Y and h2: Y → X3 such that
is exact.
Proof. Consider the following exact sequence
Since B is hereditary, Ext1B(X3/X2,f) is surjective. Let
be a preimage of (*) in Ext1B(X3/X2,X1). Then we obtain the following commutative diagram of exact sequences
with h1 injective and h2 subjective. By construction we have that
is exact.
LEMMA. Let B be a hereditary finite-dimensional k-algebra and let X,Y be indecomposable B-modules. Suppose that Ext1B(Y,X)= 0. Then 0 ≠h ∈ HomB(X,Y) is either injective or surjective.
Proof. Let 0 ≠h ∈ HomB(X,Y). Let X → Z → Y be a factorization of h with f surjective and g injective. By 1.2 we obtain an exact sequence
By assumption this sequence splits. By Krull-Schmidt we infer that Z is isomorphic to X or isomorphic to Y.
We also note the following immediate consequence for an indecomposable module X over a hereditary finite-dimensional k-algebraB.
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- Publisher: Cambridge University PressPrint publication year: 1988